34y^2=68y

Solution for 34y^2=68y equation:

34y^2=68y

We move all terms to the left:

34y^2-(68y)=0

a = 34; b = -68; c = 0;
Δ = b2-4ac
Δ = -682-4·34·0
Δ = 4624
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4624}=68$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-68)-68}{2*34}=\frac{0}{68}
=0
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-68)+68}{2*34}=\frac{136}{68}
=2
$